# SAT Math Multiple Choice Practice Question 87: Answer and Explanation

### Next steps

- Use your browser's back button to return to your test results.
- Do another SAT math multiple choice practice tests.

**Question: 87**

**21.** If j2 > j, and j3 > j, but j2 > j3, then which of the following must be true?

A. j < -1

B. -1 < j < 0

C. 0 < j < 1

D. 1 < j < 2

E. j > 2

**Correct Answer:** B

**Explanation:**

B. The first two statements aren't unusual, but the third is a little weird. If you try a "normal" number, like 4, for j, then 42 = 16 and 43 = 64; notice that j2 isn't greater than j3, so you know j isn't a positive number greater than 2. What about a fraction, like 1/2? Then (1/2)2 = 1/4, and (1/2)3 = 1/8, and j2 > j3. But wait a minute: Now j2 and j3 are both smaller than j, which contradicts the first two statements. So how about a negative number, like -2? Well, (-2)2 = 4, which is greater than -2, but (-2)3 = -8, which isn't. So you're left with a negative fraction. Try -1/2: (-1/2)2 = 1/4, which is greater than -1/2; (-1/2)3 = -1/8, which is also greater than -1/2 because it's farther to the right on a number line. And, finally, 1/4 > -1/8, so the third condition is satisfied, too. Thus, you have your answer: j is any number between 0 and -1.