SAT Subject Physics Practice Question 128: Answer and Explanation

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Question: 128

1. How much heat is required to raise the temperature of a 0.04 kg stainless steel spoon from 20°C to 50°C if the specific heat of stainless steel is 0.50 kJ/kg × °C ?

A. 200 J
B. 400 J
C. 600 J
D. 800 J
E. 1,000 J

Correct Answer: C

Explanation:

Use the equation Q = mcT.

Q = (0.04 kg)(0.50 kJ/kg • °C)(50°C − 20°C)=0.6 kJ = 600 J

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