SAT Subject Physics Practice Question 135: Answer and Explanation

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Question: 135

8. What’s the total work performed on the gas as it’s transformed from state a to state c, along the path indicated?

A. 1,500 J
B. 3,000 J
C. 4,500 J
D. 5,000 J
E. 9,500 J

Correct Answer: C


No work is done during the step from state b to state c because the volume doesn’t change. Therefore, the work done from a to c is equal to the work done from a to b. Since the pressure remains constant (this step is isobaric), we find that W = PV = (3.0 × 105 Pa)[(25 – 10) × 10–3 m3] = 4,500 J.

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