SAT Subject Physics Practice Question 276: Answer and Explanation

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Question: 276

47. The potential difference between the plates of a charged, parallel-plate capacitor is equal to X volts. If the amount of charge on the POSITIVE plate is equal to Y coulombs, what is the capacitance (in farads)?

A.
B.
C.
D.
E.

Correct Answer: C

Explanation:

Don’t let the emphasis of the word “positive” in the question throw you. In the equation Q = CV, Q is the magnitude of charge on either the positive or the negative plate of the capacitor. So, in this case, Y = CX, which gives us C = Y/X.

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